In Young's double slit experiment,the phase d | vedclass

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(D) For constructive interference,the path difference $\Delta x$ for the $n^{th}$ bright fringe is given by $\Delta x = n\lambda$,where $n$ is the ord

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$6\pi$

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(D) For constructive interference,the path difference $\Delta x$ for the $n^{th}$ bright fringe is given by $\Delta x = n\lambda$,where $n$ is the order of the fringe.For the third bright fringe,$n = 3$,so the path difference is $\Delta x = 3\lambda$.The relationship between phase difference $\phi$ and path difference $\Delta x$ is given by $\phi = \frac{2\pi}{\lambda} 	imes \Delta x$.Substituting the value of $\Delta x$,we get $\phi = \frac{2\pi}{\lambda} 	imes 3\lambda = 6\pi$.Therefore,the phase difference is $6\pi$.

In Young's double slit experiment,the phase difference between the light waves reaching the third bright fringe from the central fringe is: $(\lambda = 6000 \ \mathring{A})$

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